b2=49/9

Solution for b2=49/9 equation:

b2=49/9

We move all terms to the left:

b2-(49/9)=0

We add all the numbers together, and all the variables

b2-(+49/9)=0

We add all the numbers together, and all the variables

b^2-(+49/9)=0

We get rid of parentheses

b^2-49/9=0

We multiply all the terms by the denominator


b^2*9-49=0

Wy multiply elements

9b^2-49=0

a = 9; b = 0; c = -49;
Δ = b2-4ac
Δ = 02-4·9·(-49)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-42}{2*9}=\frac{-42}{18}
=-2+1/3
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+42}{2*9}=\frac{42}{18}
=2+1/3
$