b=(16-2a)/2

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Solution for b=(16-2a)/2 equation: 


x in (-oo:+oo)

b = (16-(2*a))/2 // - (16-(2*a))/2

b-((16-(2*a))/2) = 0

b-((16-2*a)/2) = 0

(-1*(16-2*a))/2+b = 0

(-1*(16-2*a))/2+(2*b)/2 = 0

2*b-1*(16-2*a) = 0

2*a+2*b-16 = 0

(2*a+2*b-16)/2 = 0

(2*a+2*b-16)/2 = 0 // * 2

2*a+2*b-16 = 0

x belongs to the empty set

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