b=(2d-c)/d

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Solution for b=(2d-c)/d equation: 


x in (-oo:+oo)

b = (2*d-c)/d // - (2*d-c)/d

b-((2*d-c)/d) = 0

(-1*(2*d-c))/d+b = 0

(-1*(2*d-c))/d+(b*d)/d = 0

b*d-1*(2*d-c) = 0

c-2*d+b*d = 0

(c-2*d+b*d)/d = 0

(c-2*d+b*d)/d = 0 // * d

c-2*d+b*d = 0

x belongs to the empty set

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