b=(2f+3z)/2a

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Solution for b=(2f+3z)/2a equation: 


x in (-oo:+oo)

b = a*((2*f+3*z)/2) // - a*((2*f+3*z)/2)

b-(a*((2*f+3*z)/2)) = 0

(-1*a*(2*f+3*z))/2+b = 0

(-1*a*(2*f+3*z))/2+(2*b)/2 = 0

2*b-1*a*(2*f+3*z) = 0

2*b-3*a*z-2*a*f = 0

(2*b-3*a*z-2*a*f)/2 = 0

(2*b-3*a*z-2*a*f)/2 = 0 // * 2

2*b-3*a*z-2*a*f = 0

x belongs to the empty set

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