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x in (-oo:+oo)
b = (5*d-c)/d // - (5*d-c)/d
b-((5*d-c)/d) = 0
(-1*(5*d-c))/d+b = 0
(-1*(5*d-c))/d+(b*d)/d = 0
b*d-1*(5*d-c) = 0
c-5*d+b*d = 0
(c-5*d+b*d)/d = 0
(c-5*d+b*d)/d = 0 // * d
c-5*d+b*d = 0
x belongs to the empty set
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