b=(b+1)+(b-1)+(b+3)+(2b)

Solution for b=(b+1)+(b-1)+(b+3)+(2b) equation:

Simplifying
b = (b + 1) + (b + -1) + (b + 3) + (2b)

Reorder the terms:
b = (1 + b) + (b + -1) + (b + 3) + (2b)

Remove parenthesis around (1 + b)
b = 1 + b + (b + -1) + (b + 3) + (2b)

Reorder the terms:
b = 1 + b + (-1 + b) + (b + 3) + (2b)

Remove parenthesis around (-1 + b)
b = 1 + b + -1 + b + (b + 3) + (2b)

Reorder the terms:
b = 1 + b + -1 + b + (3 + b) + (2b)

Remove parenthesis around (3 + b)
b = 1 + b + -1 + b + 3 + b + (2b)

Reorder the terms:
b = 1 + -1 + 3 + b + b + b + (2b)

Combine like terms: 1 + -1 = 0
b = 0 + 3 + b + b + b + (2b)
b = 3 + b + b + b + (2b)

Combine like terms: b + b = 2b
b = 3 + 2b + b + (2b)

Combine like terms: 2b + b = 3b
b = 3 + 3b + (2b)

Combine like terms: 3b + (2b) = 5b
b = 3 + 5b

Solving
b = 3 + 5b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5b' to each side of the equation.
b + -5b = 3 + 5b + -5b

Combine like terms: b + -5b = -4b
-4b = 3 + 5b + -5b

Combine like terms: 5b + -5b = 0
-4b = 3 + 0
-4b = 3

Divide each side by '-4'.
b = -0.75

Simplifying
b = -0.75