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b=-10-(-25/21)(6)=
We move all terms to the left:
b-(-10-(-25/21)(6))=0
We multiply all the terms by the denominator
b*21)6)-(-10-(-25=0
Wy multiply elements
21b^2-25=0
a = 21; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·21·(-25)
Δ = 2100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2100}=\sqrt{100*21}=\sqrt{100}*\sqrt{21}=10\sqrt{21}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{21}}{2*21}=\frac{0-10\sqrt{21}}{42} =-\frac{10\sqrt{21}}{42} =-\frac{5\sqrt{21}}{21} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{21}}{2*21}=\frac{0+10\sqrt{21}}{42} =\frac{10\sqrt{21}}{42} =\frac{5\sqrt{21}}{21} $
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