b=1/3=2

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Solution for b=1/3=2 equation: 


(-4*e^-2*x)/(e^-5*x) = 0

tan(x)*ln((x^2+1)^(1/2))

(2/3)*a^2 = 23

1*x^3+3*x^2+0*x-4 = 0

3*x^2+0*x^3+0*x-4 = 0

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