b=122b-3

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Solution for b=122b-3 equation: 



b=122b-3

We move all terms to the left:

b-(122b-3)=0

We get rid of parentheses

b-122b+3=0

We add all the numbers together, and all the variables

-121b+3=0

We move all terms containing b to the left, all other terms to the right

-121b=-3

b=-3/-121

b=3/121

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