b=14+2(3+b)+1

Solution for b=14+2(3+b)+1 equation:

b=14+2(3+b)+1

We move all terms to the left:

b-(14+2(3+b)+1)=0

We add all the numbers together, and all the variables

b-(14+2(b+3)+1)=0


We calculate terms in parentheses: -(14+2(b+3)+1), so:

14+2(b+3)+1

determiningTheFunctionDomain
2(b+3)+14+1

We add all the numbers together, and all the variables

2(b+3)+15

We multiply parentheses

2b+6+15

We add all the numbers together, and all the variables

2b+21

Back to the equation:

-(2b+21)


We get rid of parentheses

b-2b-21=0

We add all the numbers together, and all the variables

-1b-21=0

We move all terms containing b to the left, all other terms to the right

-b=21

b=21/-1

b=-21