b=14+2(3-b)+

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Solution for b=14+2(3-b)+ equation: 



b=14+2(3-b)+

We move all terms to the left:

b-(14+2(3-b)+)=0

We add all the numbers together, and all the variables

b-(14+2(-1b+3)+)=0



We calculate terms in parentheses: -(14+2(-1b+3)+), so:

14+2(-1b+3)+

determiningTheFunctionDomain
2(-1b+3)+14+

We add all the numbers together, and all the variables

2(-1b+3)

We multiply parentheses

-2b+6

Back to the equation:

-(-2b+6)



We get rid of parentheses

b+2b-6=0

We add all the numbers together, and all the variables

3b-6=0

We move all terms containing b to the left, all other terms to the right

3b=6

b=6/3

b=2

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