b=2(3/2b)-4

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Solution for b=2(3/2b)-4 equation: 



b=2(3/2b)-4

We move all terms to the left:

b-(2(3/2b)-4)=0



Domain of the equation: 2b)-4)!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

b-(2(+3/2b)-4)=0

We multiply all the terms by the denominator


b*2b)-4)-(2(+3=0

Wy multiply elements

2b^2+3=0

a = 2; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·2·3
Δ = -24
Delta is less than zero, so there is no solution for the equation

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