b=2/3(h-1)

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Solution for b=2/3(h-1) equation: 


x in (-oo:+oo)

b = (2/3)*(h-1) // - (2/3)*(h-1)

b-((2/3)*(h-1)) = 0

(-2/3)*(h-1)+b = 0

b-2/3*(h-1) = 0

b-2/3*(h-1) = 0

b-2/3*h+2/3 = 0

b-2/3*h+2/3 = 0

x belongs to the empty set

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