b=4/3(j-4)

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Solution for b=4/3(j-4) equation: 


x in (-oo:+oo)

b = (4/3)*(j-4) // - (4/3)*(j-4)

b-((4/3)*(j-4)) = 0

(-4/3)*(j-4)+b = 0

b-4/3*(j-4) = 0

b-4/3*(j-4) = 0

b-4/3*j+16/3 = 0

b-4/3*j+16/3 = 0

x belongs to the empty set

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