b=42+3b

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Solution for b=42+3b equation: 



b=42+3b

We move all terms to the left:

b-(42+3b)=0

We add all the numbers together, and all the variables

b-(3b+42)=0

We get rid of parentheses

b-3b-42=0

We add all the numbers together, and all the variables

-2b-42=0

We move all terms containing b to the left, all other terms to the right

-2b=42

b=42/-2

b=-21

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