b=6/5(j-39)

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Solution for b=6/5(j-39) equation: 


x in (-oo:+oo)

b = (6/5)*(j-39) // - (6/5)*(j-39)

b-((6/5)*(j-39)) = 0

(-6/5)*(j-39)+b = 0

b-6/5*(j-39) = 0

b-6/5*(j-39) = 0

b-6/5*j+234/5 = 0

b-6/5*j+234/5 = 0

x belongs to the empty set

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