b=7/6(j-27)

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Solution for b=7/6(j-27) equation: 


x in (-oo:+oo)

b = (7/6)*(j-27) // - (7/6)*(j-27)

b-((7/6)*(j-27)) = 0

(-7/6)*(j-27)+b = 0

b-7/6*(j-27) = 0

b-7/6*(j-27) = 0

b-7/6*j+63/2 = 0

b-7/6*j+63/2 = 0

x belongs to the empty set

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