b=8/3(j-68)

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Solution for b=8/3(j-68) equation: 


x in (-oo:+oo)

b = (8/3)*(j-68) // - (8/3)*(j-68)

b-((8/3)*(j-68)) = 0

(-8/3)*(j-68)+b = 0

b-8/3*(j-68) = 0

b-8/3*(j-68) = 0

b-8/3*j+544/3 = 0

b-8/3*j+544/3 = 0

x belongs to the empty set

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