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b=9+(9+1/2b)
We move all terms to the left:
b-(9+(9+1/2b))=0
Domain of the equation: 2b))!=0We add all the numbers together, and all the variables
b!=0/1
b!=0
b∈R
b-(9+(1/2b+9))=0
We multiply all the terms by the denominator
b*2b+9))-(9+(1=0
We add all the numbers together, and all the variables
b*2b=0
Wy multiply elements
2b^2=0
a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$b=\frac{-b}{2a}=\frac{0}{4}=0$
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