b=b12b-3(4b-8)-8(3b+1)

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Solution for b=b12b-3(4b-8)-8(3b+1) equation: 



b=b12b-3(4b-8)-8(3b+1)

We move all terms to the left:

b-(b12b-3(4b-8)-8(3b+1))=0



We calculate terms in parentheses: -(b12b-3(4b-8)-8(3b+1)), so:

b12b-3(4b-8)-8(3b+1)

We multiply parentheses

b12b-12b-24b+24-8

We add all the numbers together, and all the variables

-36b+b12b+16

Back to the equation:

-(-36b+b12b+16)



We get rid of parentheses

b+36b-b12b-16=0

We add all the numbers together, and all the variables

37b-b12b-16=0

We move all terms containing b to the left, all other terms to the right

37b-b12b=16

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