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Simplifying bd = ac Solving bd = ac Solving for variable 'b'. Move all terms containing b to the left, all other terms to the right. Divide each side by 'd'. b = acd-1 Simplifying b = acd-1
| 15=y+9 | | 2x^5/2x | | z=2b | | t+2(21)=62 | | zb=2ad | | u+9=14 | | 5/3n-4=21 | | 7.4y-6.4y+4.2=-1.4 | | 3/4x+2/7x=9/4 | | b/d=2a/z | | 13=u-11 | | [-3+(-10)]+[-20+17]= | | 3n-1+3n-1=n+3 | | 3/4x+2/7=9/4 | | x+1/5=3x-2/7 | | 4x/(x+1)=7-(4/(x+1)) | | -11(y-z)= | | 5/6=2n/n-3 | | 3(4n-5)-4=52 | | 3n-7=4n-37 | | 2[-7+4(-2+4)]= | | 0.5c(c+2.8)-c=0.6c+0.3 | | 2x^3-9x^2+3x+4=0 | | (8x10^-4+10^-3x)/0.8-x | | 3x5x51/4x2 | | y/3-1/2y | | x^2+4y^2-48+20=0 | | -(5x-6y+8)= | | 5y+7=8y-4y | | 32-(3x+6)=3(x+4)+x | | 7z+10-3z=8+3z-8 | | 32-(3x+6)=3x(x+4)+x |