c(10c+1)=9

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Solution for c(10c+1)=9 equation:


Simplifying
c(10c + 1) = 9

Reorder the terms:
c(1 + 10c) = 9
(1 * c + 10c * c) = 9
(1c + 10c2) = 9

Solving
1c + 10c2 = 9

Solving for variable 'c'.

Reorder the terms:
-9 + 1c + 10c2 = 9 + -9

Combine like terms: 9 + -9 = 0
-9 + 1c + 10c2 = 0

Factor a trinomial.
(-1 + -1c)(9 + -10c) = 0

Subproblem 1

Set the factor '(-1 + -1c)' equal to zero and attempt to solve: Simplifying -1 + -1c = 0 Solving -1 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -1c = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -1c = 0 + 1 -1c = 0 + 1 Combine like terms: 0 + 1 = 1 -1c = 1 Divide each side by '-1'. c = -1 Simplifying c = -1

Subproblem 2

Set the factor '(9 + -10c)' equal to zero and attempt to solve: Simplifying 9 + -10c = 0 Solving 9 + -10c = 0 Move all terms containing c to the left, all other terms to the right. Add '-9' to each side of the equation. 9 + -9 + -10c = 0 + -9 Combine like terms: 9 + -9 = 0 0 + -10c = 0 + -9 -10c = 0 + -9 Combine like terms: 0 + -9 = -9 -10c = -9 Divide each side by '-10'. c = 0.9 Simplifying c = 0.9

Solution

c = {-1, 0.9}

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