c(21-c)=110

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Solution for c(21-c)=110 equation:


Simplifying
c(21 + -1c) = 110
(21 * c + -1c * c) = 110
(21c + -1c2) = 110

Solving
21c + -1c2 = 110

Solving for variable 'c'.

Reorder the terms:
-110 + 21c + -1c2 = 110 + -110

Combine like terms: 110 + -110 = 0
-110 + 21c + -1c2 = 0

Factor a trinomial.
(-11 + c)(10 + -1c) = 0

Subproblem 1

Set the factor '(-11 + c)' equal to zero and attempt to solve: Simplifying -11 + c = 0 Solving -11 + c = 0 Move all terms containing c to the left, all other terms to the right. Add '11' to each side of the equation. -11 + 11 + c = 0 + 11 Combine like terms: -11 + 11 = 0 0 + c = 0 + 11 c = 0 + 11 Combine like terms: 0 + 11 = 11 c = 11 Simplifying c = 11

Subproblem 2

Set the factor '(10 + -1c)' equal to zero and attempt to solve: Simplifying 10 + -1c = 0 Solving 10 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + -1c = 0 + -10 Combine like terms: 10 + -10 = 0 0 + -1c = 0 + -10 -1c = 0 + -10 Combine like terms: 0 + -10 = -10 -1c = -10 Divide each side by '-1'. c = 10 Simplifying c = 10

Solution

c = {11, 10}

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