c(2c+1)=78

Solution for c(2c+1)=78 equation:

Simplifying
c(2c + 1) = 78

Reorder the terms:
c(1 + 2c) = 78
(1 * c + 2c * c) = 78
(1c + 2c2) = 78

Solving
1c + 2c2 = 78

Solving for variable 'c'.

Reorder the terms:
-78 + 1c + 2c2 = 78 + -78

Combine like terms: 78 + -78 = 0
-78 + 1c + 2c2 = 0

Factor a trinomial.
(-13 + -2c)(6 + -1c) = 0

Subproblem 1
Set the factor '(-13 + -2c)' equal to zero and attempt to solve:

Simplifying
-13 + -2c = 0

Solving
-13 + -2c = 0

Move all terms containing c to the left, all other terms to the right.

Add '13' to each side of the equation.
-13 + 13 + -2c = 0 + 13

Combine like terms: -13 + 13 = 0
0 + -2c = 0 + 13
-2c = 0 + 13

Combine like terms: 0 + 13 = 13
-2c = 13

Divide each side by '-2'.
c = -6.5

Simplifying
c = -6.5
Subproblem 2
Set the factor '(6 + -1c)' equal to zero and attempt to solve:

Simplifying
6 + -1c = 0

Solving
6 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -1c = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -1c = 0 + -6
-1c = 0 + -6

Combine like terms: 0 + -6 = -6
-1c = -6

Divide each side by '-1'.
c = 6

Simplifying
c = 6
Solution
c = {-6.5, 6}