c(2c+4)+2(7-c*2)=40

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Solution for c(2c+4)+2(7-c*2)=40 equation: 


Simplifying
c(2c + 4) + 2(7 + -1c * 2) = 40

Reorder the terms:
c(4 + 2c) + 2(7 + -1c * 2) = 40
(4 * c + 2c * c) + 2(7 + -1c * 2) = 40
(4c + 2c2) + 2(7 + -1c * 2) = 40

Reorder the terms for easier multiplication:
4c + 2c2 + 2(7 + -1 * 2c) = 40

Multiply -1 * 2
4c + 2c2 + 2(7 + -2c) = 40
4c + 2c2 + (7 * 2 + -2c * 2) = 40
4c + 2c2 + (14 + -4c) = 40

Reorder the terms:
14 + 4c + -4c + 2c2 = 40

Combine like terms: 4c + -4c = 0
14 + 0 + 2c2 = 40
14 + 2c2 = 40

Solving
14 + 2c2 = 40

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-14' to each side of the equation.
14 + -14 + 2c2 = 40 + -14

Combine like terms: 14 + -14 = 0
0 + 2c2 = 40 + -14
2c2 = 40 + -14

Combine like terms: 40 + -14 = 26
2c2 = 26

Divide each side by '2'.
c2 = 13

Simplifying
c2 = 13

Take the square root of each side:
c = {-3.605551275, 3.605551275}

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