c(2c+4)+2(7-c2)=40

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Solution for c(2c+4)+2(7-c2)=40 equation: 



c(2c+4)+2(7-c2)=40

We move all terms to the left:

c(2c+4)+2(7-c2)-(40)=0

We add all the numbers together, and all the variables

2(-1c^2+7)+c(2c+4)-40=0

We multiply parentheses

-2c^2+2c^2+4c+14-40=0

We add all the numbers together, and all the variables

4c-26=0

We move all terms containing c to the left, all other terms to the right

4c=26

c=26/4

c=6+1/2

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