c(2c+5)+3(2c+5)=

Solution for c(2c+5)+3(2c+5)= equation:

Simplifying
c(2c + 5) + 3(2c + 5) = 0

Reorder the terms:
c(5 + 2c) + 3(2c + 5) = 0
(5 * c + 2c * c) + 3(2c + 5) = 0
(5c + 2c2) + 3(2c + 5) = 0

Reorder the terms:
5c + 2c2 + 3(5 + 2c) = 0
5c + 2c2 + (5 * 3 + 2c * 3) = 0
5c + 2c2 + (15 + 6c) = 0

Reorder the terms:
15 + 5c + 6c + 2c2 = 0

Combine like terms: 5c + 6c = 11c
15 + 11c + 2c2 = 0

Solving
15 + 11c + 2c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(3 + c)(5 + 2c) = 0

Subproblem 1
Set the factor '(3 + c)' equal to zero and attempt to solve:

Simplifying
3 + c = 0

Solving
3 + c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + c = 0 + -3

Combine like terms: 3 + -3 = 0
0 + c = 0 + -3
c = 0 + -3

Combine like terms: 0 + -3 = -3
c = -3

Simplifying
c = -3
Subproblem 2
Set the factor '(5 + 2c)' equal to zero and attempt to solve:

Simplifying
5 + 2c = 0

Solving
5 + 2c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + 2c = 0 + -5

Combine like terms: 5 + -5 = 0
0 + 2c = 0 + -5
2c = 0 + -5

Combine like terms: 0 + -5 = -5
2c = -5

Divide each side by '2'.
c = -2.5

Simplifying
c = -2.5
Solution
c = {-3, -2.5}