c(3-c)=5

Solution for c(3-c)=5 equation:

Simplifying
c(3 + -1c) = 5
(3 * c + -1c * c) = 5
(3c + -1c2) = 5

Solving
3c + -1c2 = 5

Solving for variable 'c'.

Reorder the terms:
-5 + 3c + -1c2 = 5 + -5

Combine like terms: 5 + -5 = 0
-5 + 3c + -1c2 = 0

Begin completing the square.  Divide all terms by
-1 the coefficient of the squared term: 

Divide each side by '-1'.
5 + -3c + c2 = 0

Move the constant term to the right:

Add '-5' to each side of the equation.
5 + -3c + -5 + c2 = 0 + -5

Reorder the terms:
5 + -5 + -3c + c2 = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -3c + c2 = 0 + -5
-3c + c2 = 0 + -5

Combine like terms: 0 + -5 = -5
-3c + c2 = -5

The c term is -3c.  Take half its coefficient (-1.5).
Square it (2.25) and add it to both sides.

Add '2.25' to each side of the equation.
-3c + 2.25 + c2 = -5 + 2.25

Reorder the terms:
2.25 + -3c + c2 = -5 + 2.25

Combine like terms: -5 + 2.25 = -2.75
2.25 + -3c + c2 = -2.75

Factor a perfect square on the left side:
(c + -1.5)(c + -1.5) = -2.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.