c(41+10c)-18=0

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Solution for c(41+10c)-18=0 equation:


Simplifying
c(41 + 10c) + -18 = 0
(41 * c + 10c * c) + -18 = 0
(41c + 10c2) + -18 = 0

Reorder the terms:
-18 + 41c + 10c2 = 0

Solving
-18 + 41c + 10c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-9 + -2c)(2 + -5c) = 0

Subproblem 1

Set the factor '(-9 + -2c)' equal to zero and attempt to solve: Simplifying -9 + -2c = 0 Solving -9 + -2c = 0 Move all terms containing c to the left, all other terms to the right. Add '9' to each side of the equation. -9 + 9 + -2c = 0 + 9 Combine like terms: -9 + 9 = 0 0 + -2c = 0 + 9 -2c = 0 + 9 Combine like terms: 0 + 9 = 9 -2c = 9 Divide each side by '-2'. c = -4.5 Simplifying c = -4.5

Subproblem 2

Set the factor '(2 + -5c)' equal to zero and attempt to solve: Simplifying 2 + -5c = 0 Solving 2 + -5c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -5c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -5c = 0 + -2 -5c = 0 + -2 Combine like terms: 0 + -2 = -2 -5c = -2 Divide each side by '-5'. c = 0.4 Simplifying c = 0.4

Solution

c = {-4.5, 0.4}

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