c(5c+17)=12

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Solution for c(5c+17)=12 equation:


Simplifying
c(5c + 17) = 12

Reorder the terms:
c(17 + 5c) = 12
(17 * c + 5c * c) = 12
(17c + 5c2) = 12

Solving
17c + 5c2 = 12

Solving for variable 'c'.

Reorder the terms:
-12 + 17c + 5c2 = 12 + -12

Combine like terms: 12 + -12 = 0
-12 + 17c + 5c2 = 0

Factor a trinomial.
(-4 + -1c)(3 + -5c) = 0

Subproblem 1

Set the factor '(-4 + -1c)' equal to zero and attempt to solve: Simplifying -4 + -1c = 0 Solving -4 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -1c = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -1c = 0 + 4 -1c = 0 + 4 Combine like terms: 0 + 4 = 4 -1c = 4 Divide each side by '-1'. c = -4 Simplifying c = -4

Subproblem 2

Set the factor '(3 + -5c)' equal to zero and attempt to solve: Simplifying 3 + -5c = 0 Solving 3 + -5c = 0 Move all terms containing c to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -5c = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -5c = 0 + -3 -5c = 0 + -3 Combine like terms: 0 + -3 = -3 -5c = -3 Divide each side by '-5'. c = 0.6 Simplifying c = 0.6

Solution

c = {-4, 0.6}

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