c(8c+1)=7

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Solution for c(8c+1)=7 equation:


Simplifying
c(8c + 1) = 7

Reorder the terms:
c(1 + 8c) = 7
(1 * c + 8c * c) = 7
(1c + 8c2) = 7

Solving
1c + 8c2 = 7

Solving for variable 'c'.

Reorder the terms:
-7 + 1c + 8c2 = 7 + -7

Combine like terms: 7 + -7 = 0
-7 + 1c + 8c2 = 0

Factor a trinomial.
(-1 + -1c)(7 + -8c) = 0

Subproblem 1

Set the factor '(-1 + -1c)' equal to zero and attempt to solve: Simplifying -1 + -1c = 0 Solving -1 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -1c = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -1c = 0 + 1 -1c = 0 + 1 Combine like terms: 0 + 1 = 1 -1c = 1 Divide each side by '-1'. c = -1 Simplifying c = -1

Subproblem 2

Set the factor '(7 + -8c)' equal to zero and attempt to solve: Simplifying 7 + -8c = 0 Solving 7 + -8c = 0 Move all terms containing c to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -8c = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -8c = 0 + -7 -8c = 0 + -7 Combine like terms: 0 + -7 = -7 -8c = -7 Divide each side by '-8'. c = 0.875 Simplifying c = 0.875

Solution

c = {-1, 0.875}

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