c(9c+1)=8

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Solution for c(9c+1)=8 equation:


Simplifying
c(9c + 1) = 8

Reorder the terms:
c(1 + 9c) = 8
(1 * c + 9c * c) = 8
(1c + 9c2) = 8

Solving
1c + 9c2 = 8

Solving for variable 'c'.

Reorder the terms:
-8 + 1c + 9c2 = 8 + -8

Combine like terms: 8 + -8 = 0
-8 + 1c + 9c2 = 0

Factor a trinomial.
(-1 + -1c)(8 + -9c) = 0

Subproblem 1

Set the factor '(-1 + -1c)' equal to zero and attempt to solve: Simplifying -1 + -1c = 0 Solving -1 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -1c = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -1c = 0 + 1 -1c = 0 + 1 Combine like terms: 0 + 1 = 1 -1c = 1 Divide each side by '-1'. c = -1 Simplifying c = -1

Subproblem 2

Set the factor '(8 + -9c)' equal to zero and attempt to solve: Simplifying 8 + -9c = 0 Solving 8 + -9c = 0 Move all terms containing c to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + -9c = 0 + -8 Combine like terms: 8 + -8 = 0 0 + -9c = 0 + -8 -9c = 0 + -8 Combine like terms: 0 + -8 = -8 -9c = -8 Divide each side by '-9'. c = 0.8888888889 Simplifying c = 0.8888888889

Solution

c = {-1, 0.8888888889}

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