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Simplifying c(c + 12) = 5(3 + 2c) Reorder the terms: c(12 + c) = 5(3 + 2c) (12 * c + c * c) = 5(3 + 2c) (12c + c2) = 5(3 + 2c) 12c + c2 = (3 * 5 + 2c * 5) 12c + c2 = (15 + 10c) Solving 12c + c2 = 15 + 10c Solving for variable 'c'. Reorder the terms: -15 + 12c + -10c + c2 = 15 + 10c + -15 + -10c Combine like terms: 12c + -10c = 2c -15 + 2c + c2 = 15 + 10c + -15 + -10c Reorder the terms: -15 + 2c + c2 = 15 + -15 + 10c + -10c Combine like terms: 15 + -15 = 0 -15 + 2c + c2 = 0 + 10c + -10c -15 + 2c + c2 = 10c + -10c Combine like terms: 10c + -10c = 0 -15 + 2c + c2 = 0 Factor a trinomial. (-5 + -1c)(3 + -1c) = 0Subproblem 1
Set the factor '(-5 + -1c)' equal to zero and attempt to solve: Simplifying -5 + -1c = 0 Solving -5 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -1c = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -1c = 0 + 5 -1c = 0 + 5 Combine like terms: 0 + 5 = 5 -1c = 5 Divide each side by '-1'. c = -5 Simplifying c = -5Subproblem 2
Set the factor '(3 + -1c)' equal to zero and attempt to solve: Simplifying 3 + -1c = 0 Solving 3 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -1c = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -1c = 0 + -3 -1c = 0 + -3 Combine like terms: 0 + -3 = -3 -1c = -3 Divide each side by '-1'. c = 3 Simplifying c = 3Solution
c = {-5, 3}
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