c(c+2)-5=b(x-3)

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Solution for c(c+2)-5=b(x-3) equation:


Simplifying
c(c + 2) + -5 = b(x + -3)

Reorder the terms:
c(2 + c) + -5 = b(x + -3)
(2 * c + c * c) + -5 = b(x + -3)
(2c + c2) + -5 = b(x + -3)

Reorder the terms:
-5 + 2c + c2 = b(x + -3)

Reorder the terms:
-5 + 2c + c2 = b(-3 + x)
-5 + 2c + c2 = (-3 * b + x * b)
-5 + 2c + c2 = (-3b + bx)

Solving
-5 + 2c + c2 = -3b + bx

Solving for variable 'c'.

Reorder the terms:
-5 + 3b + -1bx + 2c + c2 = -3b + bx + 3b + -1bx

Reorder the terms:
-5 + 3b + -1bx + 2c + c2 = -3b + 3b + bx + -1bx

Combine like terms: -3b + 3b = 0
-5 + 3b + -1bx + 2c + c2 = 0 + bx + -1bx
-5 + 3b + -1bx + 2c + c2 = bx + -1bx

Combine like terms: bx + -1bx = 0
-5 + 3b + -1bx + 2c + c2 = 0

The solution to this equation could not be determined.

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