c(c+2)-c(-6)=10(-2)

Solution for c(c+2)-c(-6)=10(-2) equation:

Simplifying
c(c + 2) + -1c(-6) = 10(-2)

Reorder the terms:
c(2 + c) + -1c(-6) = 10(-2)
(2 * c + c * c) + -1c(-6) = 10(-2)
(2c + c2) + -1c(-6) = 10(-2)

Reorder the terms for easier multiplication:
2c + c2 + -1 * -6c = 10(-2)

Multiply -1 * -6
2c + c2 + 6c = 10(-2)

Reorder the terms:
2c + 6c + c2 = 10(-2)

Combine like terms: 2c + 6c = 8c
8c + c2 = 10(-2)

Multiply 10 * -2
8c + c2 = -20

Solving
8c + c2 = -20

Solving for variable 'c'.

Reorder the terms:
20 + 8c + c2 = -20 + 20

Combine like terms: -20 + 20 = 0
20 + 8c + c2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-20' to each side of the equation.
20 + 8c + -20 + c2 = 0 + -20

Reorder the terms:
20 + -20 + 8c + c2 = 0 + -20

Combine like terms: 20 + -20 = 0
0 + 8c + c2 = 0 + -20
8c + c2 = 0 + -20

Combine like terms: 0 + -20 = -20
8c + c2 = -20

The c term is 8c.  Take half its coefficient (4).
Square it (16) and add it to both sides.

Add '16' to each side of the equation.
8c + 16 + c2 = -20 + 16

Reorder the terms:
16 + 8c + c2 = -20 + 16

Combine like terms: -20 + 16 = -4
16 + 8c + c2 = -4

Factor a perfect square on the left side:
(c + 4)(c + 4) = -4

Can't calculate square root of the right side.

The solution to this equation could not be determined.