c(c+4)+4=0

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Solution for c(c+4)+4=0 equation: 



c(c+4)+4=0

We multiply parentheses

c^2+4c+4=0

a = 1; b = 4; c = +4;
Δ = b2-4ac
Δ = 42-4·1·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$c=\frac{-b}{2a}=\frac{-4}{2}=-2$

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