c(c-6)=27

Solution for c(c-6)=27 equation:

Simplifying
c(c + -6) = 27

Reorder the terms:
c(-6 + c) = 27
(-6 * c + c * c) = 27
(-6c + c2) = 27

Solving
-6c + c2 = 27

Solving for variable 'c'.

Reorder the terms:
-27 + -6c + c2 = 27 + -27

Combine like terms: 27 + -27 = 0
-27 + -6c + c2 = 0

Factor a trinomial.
(-3 + -1c)(9 + -1c) = 0

Subproblem 1
Set the factor '(-3 + -1c)' equal to zero and attempt to solve:

Simplifying
-3 + -1c = 0

Solving
-3 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + -1c = 0 + 3

Combine like terms: -3 + 3 = 0
0 + -1c = 0 + 3
-1c = 0 + 3

Combine like terms: 0 + 3 = 3
-1c = 3

Divide each side by '-1'.
c = -3

Simplifying
c = -3
Subproblem 2
Set the factor '(9 + -1c)' equal to zero and attempt to solve:

Simplifying
9 + -1c = 0

Solving
9 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + -1c = 0 + -9

Combine like terms: 9 + -9 = 0
0 + -1c = 0 + -9
-1c = 0 + -9

Combine like terms: 0 + -9 = -9
-1c = -9

Divide each side by '-1'.
c = 9

Simplifying
c = 9
Solution
c = {-3, 9}