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c*c=135
We move all terms to the left:
c*c-(135)=0
Wy multiply elements
c^2-135=0
a = 1; b = 0; c = -135;
Δ = b2-4ac
Δ = 02-4·1·(-135)
Δ = 540
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{540}=\sqrt{36*15}=\sqrt{36}*\sqrt{15}=6\sqrt{15}$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{15}}{2*1}=\frac{0-6\sqrt{15}}{2} =-\frac{6\sqrt{15}}{2} =-3\sqrt{15} $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{15}}{2*1}=\frac{0+6\sqrt{15}}{2} =\frac{6\sqrt{15}}{2} =3\sqrt{15} $
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