c+(2c+4)=(c+2c)+4

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Solution for c+(2c+4)=(c+2c)+4 equation: 


Simplifying
c + (2c + 4) = (c + 2c) + 4

Reorder the terms:
c + (4 + 2c) = (c + 2c) + 4

Remove parenthesis around (4 + 2c)
c + 4 + 2c = (c + 2c) + 4

Reorder the terms:
4 + c + 2c = (c + 2c) + 4

Combine like terms: c + 2c = 3c
4 + 3c = (c + 2c) + 4

Combine like terms: c + 2c = 3c
4 + 3c = (3c) + 4
4 + 3c = (3c) + 4

Reorder the terms:
4 + 3c = 4 + (3c)

Add '-4' to each side of the equation.
4 + -4 + 3c = 4 + -4 + (3c)

Combine like terms: 4 + -4 = 0
0 + 3c = 4 + -4 + (3c)
3c = 4 + -4 + (3c)

Combine like terms: 4 + -4 = 0
3c = 0 + (3c)
3c = (3c)

Add '-3c' to each side of the equation.
3c + -3c = (3c) + -3c

Combine like terms: 3c + -3c = 0
0 = (3c) + -3c

Combine like terms: (3c) + -3c = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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