c+(c+2)+(c+4)=24

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Solution for c+(c+2)+(c+4)=24 equation:


Simplifying
c + (c + 2) + (c + 4) = 24

Reorder the terms:
c + (2 + c) + (c + 4) = 24

Remove parenthesis around (2 + c)
c + 2 + c + (c + 4) = 24

Reorder the terms:
c + 2 + c + (4 + c) = 24

Remove parenthesis around (4 + c)
c + 2 + c + 4 + c = 24

Reorder the terms:
2 + 4 + c + c + c = 24

Combine like terms: 2 + 4 = 6
6 + c + c + c = 24

Combine like terms: c + c = 2c
6 + 2c + c = 24

Combine like terms: 2c + c = 3c
6 + 3c = 24

Solving
6 + 3c = 24

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 3c = 24 + -6

Combine like terms: 6 + -6 = 0
0 + 3c = 24 + -6
3c = 24 + -6

Combine like terms: 24 + -6 = 18
3c = 18

Divide each side by '3'.
c = 6

Simplifying
c = 6

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