c+(c+2)+(c+4)=2c+3+(c+4)

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Solution for c+(c+2)+(c+4)=2c+3+(c+4) equation: 



c+(c+2)+(c+4)=2c+3+(c+4)

We move all terms to the left:

c+(c+2)+(c+4)-(2c+3+(c+4))=0

We get rid of parentheses

c+c+c-(2c+3+(c+4))+2+4=0



We calculate terms in parentheses: -(2c+3+(c+4)), so:

2c+3+(c+4)

determiningTheFunctionDomain
2c+(c+4)+3

We get rid of parentheses

2c+c+4+3

We add all the numbers together, and all the variables

3c+7

Back to the equation:

-(3c+7)



We add all the numbers together, and all the variables

3c-(3c+7)+6=0

We get rid of parentheses

3c-3c-7+6=0

We add all the numbers together, and all the variables

-1!=0

There is no solution for this equation

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