c+(c+2)=(c+4)=27

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Solution for c+(c+2)=(c+4)=27 equation: 



c+(c+2)=(c+4)=27

We move all terms to the left:

c+(c+2)-((c+4))=0

We get rid of parentheses

c+c-((c+4))+2=0



We calculate terms in parentheses: -((c+4)), so:

(c+4)

We get rid of parentheses

c+4

Back to the equation:

-(c+4)



We add all the numbers together, and all the variables

2c-(c+4)+2=0

We get rid of parentheses

2c-c-4+2=0

We add all the numbers together, and all the variables

c-2=0

We move all terms containing c to the left, all other terms to the right

c=2

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