c+1+2(2c-3)=4c+5

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Solution for c+1+2(2c-3)=4c+5 equation:


Simplifying
c + 1 + 2(2c + -3) = 4c + 5

Reorder the terms:
c + 1 + 2(-3 + 2c) = 4c + 5
c + 1 + (-3 * 2 + 2c * 2) = 4c + 5
c + 1 + (-6 + 4c) = 4c + 5

Reorder the terms:
1 + -6 + c + 4c = 4c + 5

Combine like terms: 1 + -6 = -5
-5 + c + 4c = 4c + 5

Combine like terms: c + 4c = 5c
-5 + 5c = 4c + 5

Reorder the terms:
-5 + 5c = 5 + 4c

Solving
-5 + 5c = 5 + 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
-5 + 5c + -4c = 5 + 4c + -4c

Combine like terms: 5c + -4c = 1c
-5 + 1c = 5 + 4c + -4c

Combine like terms: 4c + -4c = 0
-5 + 1c = 5 + 0
-5 + 1c = 5

Add '5' to each side of the equation.
-5 + 5 + 1c = 5 + 5

Combine like terms: -5 + 5 = 0
0 + 1c = 5 + 5
1c = 5 + 5

Combine like terms: 5 + 5 = 10
1c = 10

Divide each side by '1'.
c = 10

Simplifying
c = 10

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