c+10+3c-6+12c+48=180

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Solution for c+10+3c-6+12c+48=180 equation: 



c+10+3c-6+12c+48=180

We move all terms to the left:

c+10+3c-6+12c+48-(180)=0

We add all the numbers together, and all the variables

16c-128=0

We move all terms containing c to the left, all other terms to the right

16c=128

c=128/16

c=8

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