c+11/3c=4

Solution for c+11/3c=4 equation:

c+11/3c=4

We move all terms to the left:

c+11/3c-(4)=0


Domain of the equation: 3c!=0

c!=0/3

c!=0

c∈R


We multiply all the terms by the denominator


c*3c-4*3c+11=0

Wy multiply elements

3c^2-12c+11=0

a = 3; b = -12; c = +11;
Δ = b2-4ac
Δ = -122-4·3·11
Δ = 12
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12}=\sqrt{4*3}=\sqrt{4}*\sqrt{3}=2\sqrt{3}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-2\sqrt{3}}{2*3}=\frac{12-2\sqrt{3}}{6}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+2\sqrt{3}}{2*3}=\frac{12+2\sqrt{3}}{6}
$