c+20/12=3

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Solution for c+20/12=3 equation: 



c+20/12=3

We move all terms to the left:

c+20/12-(3)=0

determiningTheFunctionDomain
c-3+20/12=0

We multiply all the terms by the denominator


c*12+20-3*12=0

We add all the numbers together, and all the variables

c*12-16=0

Wy multiply elements

12c-16=0

We move all terms containing c to the left, all other terms to the right

12c=16

c=16/12

c=1+1/3

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