c+3(1-2c)-4=6c+2(c+3)

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Solution for c+3(1-2c)-4=6c+2(c+3) equation: 



c+3(1-2c)-4=6c+2(c+3)

We move all terms to the left:

c+3(1-2c)-4-(6c+2(c+3))=0

We add all the numbers together, and all the variables

c+3(-2c+1)-(6c+2(c+3))-4=0

We multiply parentheses

c-6c-(6c+2(c+3))+3-4=0



We calculate terms in parentheses: -(6c+2(c+3)), so:

6c+2(c+3)

We multiply parentheses

6c+2c+6

We add all the numbers together, and all the variables

8c+6

Back to the equation:

-(8c+6)



We add all the numbers together, and all the variables

-5c-(8c+6)-1=0

We get rid of parentheses

-5c-8c-6-1=0

We add all the numbers together, and all the variables

-13c-7=0

We move all terms containing c to the left, all other terms to the right

-13c=7

c=7/-13

c=-7/13

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