c-4(c+5)=5(2c+9)

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Solution for c-4(c+5)=5(2c+9) equation: 



c-4(c+5)=5(2c+9)

We move all terms to the left:

c-4(c+5)-(5(2c+9))=0

We multiply parentheses

c-4c-(5(2c+9))-20=0



We calculate terms in parentheses: -(5(2c+9)), so:

5(2c+9)

We multiply parentheses

10c+45

Back to the equation:

-(10c+45)



We add all the numbers together, and all the variables

-3c-(10c+45)-20=0

We get rid of parentheses

-3c-10c-45-20=0

We add all the numbers together, and all the variables

-13c-65=0

We move all terms containing c to the left, all other terms to the right

-13c=65

c=65/-13

c=-5

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