c/23-(2c+3)=2(c+5)+c

Solution for c/23-(2c+3)=2(c+5)+c equation:

c/23-(2c+3)=2(c+5)+c

We move all terms to the left:

c/23-(2c+3)-(2(c+5)+c)=0

We get rid of parentheses

c/23-2c-(2(c+5)+c)-3=0

We multiply all the terms by the denominator


c-2c*23-((2(c+5)+c))*23-3*23=0

We add all the numbers together, and all the variables

c-2c*23-((2(c+5)+c))*23-69=0

Wy multiply elements

c-46c-((2(c+5)+c))*23-69=0

We add all the numbers together, and all the variables

-45c-((2(c+5)+c))*23-69=0

We move all terms containing c to the left, all other terms to the right

-45c-((2(c+5)+c))*23=69