If it's not what You are looking for type in the equation solver your own equation and let us solve it.
c2=21
We move all terms to the left:
c2-(21)=0
We add all the numbers together, and all the variables
c^2-21=0
a = 1; b = 0; c = -21;
Δ = b2-4ac
Δ = 02-4·1·(-21)
Δ = 84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{84}=\sqrt{4*21}=\sqrt{4}*\sqrt{21}=2\sqrt{21}$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{21}}{2*1}=\frac{0-2\sqrt{21}}{2} =-\frac{2\sqrt{21}}{2} =-\sqrt{21} $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{21}}{2*1}=\frac{0+2\sqrt{21}}{2} =\frac{2\sqrt{21}}{2} =\sqrt{21} $
| 0,2*x+6=36 | | 8y-8-3y+5=0 | | 7x-6=11-5 | | 1+x=7+4-2x | | |3x-5|=1 | | z2=4 | | 5x+9-x=13 | | 0=20x-20x^2 | | x-(x-40)÷2=130 | | 7-3z-4z=28 | | 5z=4z+3 | | 0=(20x)/((x^2)+1) | | 10x+60=12x+40 | | 256x=0.25 | | -1/6x=4 | | -4x-5=2x-11 | | -9y+15=15 | | -4x-5=2x=11 | | 3x-11/4-3-5x/8=x+6/2 | | 12x+7=5x-21 | | -4x+10=x-5 | | X=253×(2x-1) | | 7(7x=6)= | | 20=40÷z | | |6x-3|=15 | | 25^2+4=20x | | y=23^2 | | 5y-5y=2 | | 35^2+4=20x | | n=18=25 | | (4x-5)/3=(3x+7)/2 | | -2.52=3.7a-4.7a |